Postgraduate Mathematics II task 22: If 5^x=3125, enter x.
Rewrite the value using base 5: 3125 = 5^5. Matching exponents gives x = 5.
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Rewrite the value using base 5: 3125 = 5^5. Matching exponents gives x = 5.
The dot product is 4×2+6×4=32.
An antiderivative is 4/2 x²+5x. At x=5, the value is 75.0.
f′(x)=15x²+12x. Substituting x=4 gives 288.
The coordinate differences are 3 and 4, so the distance is √(3²+4²)=5.
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There are 6 favourable outcomes out of 12 equally likely outcomes, so P(red)=6/12.
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The sum is n(n+1)/2=36, so the mean is 36/8.
aₙ=a₁+(n−1)d=5+(8−1)×4=33.
By Vieta’s formula, the sum of the roots equals the coefficient 18.
Subtract 6 from both sides and divide by 6: x = (48-6)/6 = 7.
Percentage=(13/28)×100=46.43.
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Use the circle-area formula A = πr². Substituting r = 8 gives A = π × 8² = 64π.