A net force accelerates a 3 kg mass at 2 m/s². Enter the force in newtons.
Newton’s second law gives F=ma=3×2=6 N.
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Newton’s second law gives F=ma=3×2=6 N.
Speed=distance/time=120/11=10.91 m/s.
Percentage=(10/35)×100=28.57.
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Use the circle-area formula A = πr². Substituting r = 9 gives A = π × 9² = 81π.
Rewrite the value using base 5: 3125 = 5^5. Matching exponents gives x = 5.
The dot product is 4×2+2×4=16.
An antiderivative is 4/2 x²+1x. At x=5, the value is 55.0.
f′(x)=3x²+6x. Substituting x=4 gives 72.
The coordinate differences are 3 and 4, so the distance is √(3²+4²)=5.
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There are 2 favourable outcomes out of 8 equally likely outcomes, so P(red)=2/8.
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The sum is n(n+1)/2=15, so the mean is 15/5.
aₙ=a₁+(n−1)d=8+(8−1)×4=36.