Senior-secondary mathematics task 50: The roots of x² − 11x + 28 = 0 are r and s. Enter r+s.
By Vieta’s formula, the sum of the roots equals the coefficient 11.
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By Vieta’s formula, the sum of the roots equals the coefficient 11.
Subtract 8 from both sides and divide by 7: x = (50-8)/7 = 6.
Percentage=(9/24)×100=37.50.
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Use the circle-area formula A = πr². Substituting r = 6 gives A = π × 6² = 36π.
Rewrite the value using base 2: 4 = 2^2. Matching exponents gives x = 2.
The dot product is 1×3+6×5=33.
An antiderivative is 1/2 x²+5x. At x=2, the value is 12.0.
f′(x)=15x²+12x. Substituting x=1 gives 27.
The coordinate differences are 3 and 4, so the distance is √(3²+4²)=5.
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There are 6 favourable outcomes out of 13 equally likely outcomes, so P(red)=6/13.
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The sum is n(n+1)/2=36, so the mean is 36/8.
aₙ=a₁+(n−1)d=6+(9−1)×5=46.