Browse exam-wise, subject-wise, and country-wise MCQs with explanations.
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The mode is the value occurring most often.
The number 4 appears three times.
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The median is the middle value in ordered data.
The third of five values is 9.
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The sum is 40 and there are 5 values.
The mean is 40 ÷ 5 = 8.
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There are 5 letters with L repeated twice and E repeated twice.
Distinct arrangements = 5!/(2!2!) = 30.
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There are 4 choices for the first digit, then 3, then 2.
Thus, 4 × 3 × 2 = 24.
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Selection without order uses combinations.
5C2 = 5 × 4 ÷ 2 = 10.
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The number of arrangements of 5 distinct objects is 5!.
Thus, 5! = 120.
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Three distinct objects can be arranged in 3! ways.
Thus, 3! = 3 × 2 × 1 = 6.
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The probability is 4/10 × 3/9.
This simplifies to 12/90 = 2/15.
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There are 2 favorable blue balls out of 5 total balls.
The probability is therefore 2/5.
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For independent events, multiply their probabilities.
Thus, 1/2 × 1/3 = 1/6.
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An event and its complement have total probability 1.
Thus, P(not A) = 1 - 0.35 = 0.65.
