Practice ECAT Mathematics questions with answers and explanations.
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Three taps together have three times the rate of one tap.
One tap therefore takes 3 × 6 = 18 hours.
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Compound growth gives 20,000 × 1.05².
The result is 22,050.
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The remaining part is 3/4 of the tank.
At 8 hours per full tank, 3/4 takes 6 hours.
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Compound amount is P(1 + r)².
Thus, 10,000 × 1.1² = Rs. 12,100.
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Daily work equals total work divided by the number of days.
Thus, A's one-day work is 1/12.
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Daily wage equals total earnings divided by days worked.
Thus, 3,600 ÷ 12 = Rs. 300.
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The amount is 8,000 × 1.05² = Rs. 8,820.
Subtracting the principal gives compound interest of Rs. 820.
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Their combined daily rate is 1/10 + 1/15 = 1/6.
Therefore, they complete the job in 6 days.
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A's share is 3 out of 8 total parts.
Thus, A receives 3/8 × 4,800 = Rs. 1,800.
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For two years, the difference is P(r/100)².
So 10,000 × 0.1² = Rs. 100.
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B's rate is 1/8 - 1/12 = 1/24.
Therefore, B alone needs 24 days.
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Total work is proportional to workers × hours × days.
So days = 8 × 6 × 15 ÷ (12 × 5) = 12.
