Practice ECAT Mathematics questions with answers and explanations.
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Using SI = PRT/100, 900 = P × 6 × 3/100.
Solving gives P = Rs. 5,000.
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Two centimeters represent 100,000 centimeters in reality.
Since 100,000 cm = 1 km, the answer is 1 kilometer.
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Rate = SI × 100 ÷ (P × T).
Thus, 800 × 100 ÷ (4,000 × 5) = 4%.
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The difference of ratio parts is 5, corresponding to 35.
One part is 7, so the larger number is 9 × 7 = 63.
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Five parts equal Rs. 50,000, so one part is Rs. 10,000.
Expenditure is four parts, leaving one part as saving.
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Six consecutive integers centered at 17.5 are 15 through 20.
Therefore, the smallest is 15.
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The average of 1 through n is (n + 1)/2.
Setting (n + 1)/2 = 20 gives n = 39.
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The difference between C and A is 2 ratio parts, equal to Rs. 600.
One part is Rs. 300, so 12 parts total Rs. 3,600.
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Initially, milk is 42 liters and water is 18 liters.
For a 7:5 ratio with 42 liters milk, water must be 30 liters, so add 12.
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Let the numbers be 5k and 8k; then (5k + 9)/(8k + 9) = 2/3.
Solving gives k = 9, so the smaller number is 45.
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Profit equals selling price minus cost price.
Thus, 920 - 800 = Rs. 120.
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A 10% loss on Rs. 1,200 is Rs. 120.
Subtracting gives a selling price of Rs. 1,080.
