A 1000 W motor runs for 20 s. How much energy does it transfer?
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Energy transferred is Pt.
1000×20 = 20,000 J.
Practice ECAT Physics questions with answers and explanations.
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Energy transferred is Pt.
1000×20 = 20,000 J.
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Net work equals the change in kinetic energy.
Kf=20+80 = 100 J.
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Use a=F/m.
A=12/4 = 3 m/s².
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All isolated collisions conserve momentum.
Elastic collisions also conserve total kinetic energy.
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Centripetal force is mv²/r.
F=2×36/4 = 18 N.
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The objects share a common final velocity.
Momentum is conserved, but kinetic energy is not.
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Centripetal acceleration is v²/r.
A=100/20 = 5 m/s².
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Acceleration is F/m = 4 m/s².
Change in velocity is at=4×3 = 12 m/s.
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The net force is 80-20 = 60 N.
Acceleration is 60/15 = 4 m/s².
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Constant velocity means zero acceleration and zero net force.
The normal force therefore equals the person's weight, 600 N.
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Work transfers energy when a force acts through a displacement.
Only the component of force along displacement contributes.
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Kinetic energy depends on mass and speed.
For translational motion, K=½mv².