MCQ Collection
ECAT Physics MCQs
Practice ECAT Physics questions with answers and explanations.
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Correct Answer: C. The contact force perpendicular to a surface
Explanation:
A surface exerts a normal force on an object in contact with it.
Its magnitude is not always equal to weight.
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Correct Answer: C. 2 m/s²
Explanation:
Use v²=u²+2as.
100-16 = 42a, so a=2 m/s².
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Correct Answer: D. A force opposing relative motion or tendency of motion between surfaces
Explanation:
Friction acts tangentially at a contact surface.
It may be static or kinetic.
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Correct Answer: D. 20 m/s
Explanation:
Starting from rest, v=gt.
V=10×2 = 20 m/s.
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Correct Answer: A. Constant speed reached when drag balances the driving force
Explanation:
At terminal velocity, net force is zero.
The object then moves with constant velocity.
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Correct Answer: A. 45 m
Explanation:
Use s=½gt².
S=½×10×9 = 45 m.
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Correct Answer: B. The center of the circular path
Explanation:
Centripetal acceleration changes the direction of velocity.
It always points radially inward.
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Correct Answer: B. 2 s
Explanation:
At maximum height, final vertical velocity is zero.
0=20-10t gives t=2 s.
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Correct Answer: C. Any net inward force required for circular motion
Explanation:
Centripetal force is not a separate force type.
It may be supplied by tension, friction, gravity, or another force.
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Correct Answer: C. 20 m
Explanation:
Use v²=u²-2gh with v=0.
0=400-20h, so h=20 m.
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Correct Answer: D. Zero net force
Explanation:
A particle in translational equilibrium has no acceleration.
It may be at rest or moving at constant velocity.
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Correct Answer: D. 20 N
Explanation:
Newton's second law gives F=ma.
F=5×4 = 20 N.