Practice GAT Subject Mathematics questions with answers and explanations.
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After a 30% discount, 70% of the original price remains.
Thus, the original price is 840 ÷ 0.70 = 1,200.
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After a 20% increase, the quantity becomes 120% of the original.
The required reduction is 20/120 × 100 = 16⅔%.
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Convert each value to decimals: 5/8 = 0.625, 0.60 = 0.60, 59% = 0.59, and 3/5 = 0.60.
Therefore, 5/8 is the greatest.
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Multiply 2 × 3 = 6 and count three decimal places in total.
The product is 0.006.
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Multiply both numbers by 10 to remove decimals.
Then 48 ÷ 6 = 8.
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The third decimal digit is 6, so the second decimal digit is rounded up.
Thus, 18.746 becomes 18.75.
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The decrease is Rs. 75.
The percentage decrease is 75/500 × 100 = 15%.
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Let the number be x, so 0.40x = 72.
Dividing by 0.40 gives x = 180.
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The sequence increases by 3 each time.
Adding 3 to 11 gives 14.
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Percent means per hundred.
Thus, 3.5% = 3.5 ÷ 100 = 0.035.
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The sum of the first n natural numbers is n(n + 1)/2.
For n = 10, the sum is 10 × 11 ÷ 2 = 55.
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The required percentage is 45/250 × 100.
This equals 18%.
