GATE EC NAT 6: A signal is band-limited to 8 kHz. Enter the Nyquist sampling rate in kHz.
Correct Answer: 16
Explanation:
2fmax=16 kHz.
Practice GATE EC NAT questions with answers and explanations.
2fmax=16 kHz.
20log₁₀(9)=19.08 dB.
T(ns)=1000/f(MHz)=83.333.
2fmax=6 kHz.
20log₁₀(4)=12.04 dB.
T(ns)=1000/f(MHz)=25.0.