If 15 workers finish a job in 20 days, how many workers are needed to finish it in 12 days?
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Worker-days remain constant for the same job.
Thus, 15 × 20 ÷ 12 = 25 workers.
Practice GIKI Mathematics questions with answers and explanations.
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Worker-days remain constant for the same job.
Thus, 15 × 20 ÷ 12 = 25 workers.
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Twice the efficiency means twice the daily work rate.
Therefore, A takes half of 18 days, which is 9 days.
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In 5 days, A completes 5/20 = 1/4 of the job.
Therefore, 3/4 remains.
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If half the work takes 6 days, the full work takes twice as long.
Thus, the total time is 12 days.
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The taxed price is 115% of the original price.
So the original is 2,300 ÷ 1.15 = Rs. 2,000.
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Using SI = PRT/100, 900 = P × 6 × 3/100.
Solving gives P = Rs. 5,000.
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Rate = SI × 100 ÷ (P × T).
Thus, 800 × 100 ÷ (4,000 × 5) = 4%.
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Compound amount is P(1 + r)².
Thus, 10,000 × 1.1² = Rs. 12,100.
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The amount is 8,000 × 1.05² = Rs. 8,820.
Subtracting the principal gives compound interest of Rs. 820.
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For two years, the difference is P(r/100)².
So 10,000 × 0.1² = Rs. 100.
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Doubling means interest equal to the principal is earned in 8 years.
Tripling requires interest equal to twice the principal, so it takes 16 years.
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One-year compound amount is principal plus 12% interest.
Thus, 20,000 × 1.12 = Rs. 22,400.