A force of 40 N acts on a 10 kg object for 3 s. What change in velocity occurs?
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Acceleration is F/m = 4 m/s².
Change in velocity is at=4×3 = 12 m/s.
Practice GIKI Physics questions with answers and explanations.
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Acceleration is F/m = 4 m/s².
Change in velocity is at=4×3 = 12 m/s.
Choose an option to check your answer.
The net force is 80-20 = 60 N.
Acceleration is 60/15 = 4 m/s².
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Acceleration is net force divided by mass.
A=30/6 = 5 m/s².
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Weight is W=mg.
W=7×10 = 70 N.
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Vertical equilibrium requires normal force to balance weight.
N=mg=10×10 = 100 N.
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Opposing forces subtract.
Net force = 50-20 = 30 N.
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The runner returns to the starting point, so displacement is zero.
Average velocity is therefore zero.
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Use v=u+at with u=0.
V=0+3×4 = 12 m/s.
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Use v=u+at.
V=5+2×6 = 17 m/s.
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Acceleration is change in velocity divided by time.
(5-20)/3 = -5 m/s².
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Use s=ut+½at² with u=0.
S=½×2×25 = 25 m.
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Use s=ut+½at².
S=10×5+½×2×25 = 50+25 = 75 m.