JEE Main Chemistry numerical 251: If the roots of z²−40z+391=0 are r and s, enter r+s.
Correct Answer: 40
Explanation:
Vieta gives r+s=40.
Practice JEE Main Chemistry Numerical questions with answers and explanations.
Vieta gives r+s=40.
Area=½×15×11=82.5.
96
17×5=85.
190
Vieta gives r+s=31.
57
7×19=133.
Vieta gives r+s=14.
70
Area=½×10×16=80.0.
45