Algebra, arithmetic, reasoning.
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A's share is 3 out of 8 total parts.
Thus, A receives 3/8 × 4,800 = Rs. 1,800.
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For motion in the same direction, relative speed is the difference.
Thus, 80 - 55 = 25 km/h.
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Downwind speed is 300 km/h and upwind speed is 200 km/h.
Wind speed is half their difference: 50 km/h.
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Any nonzero number raised to the zero power equals 1.
Therefore, 5⁰ = 1.
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B's rate is 1/8 - 1/12 = 1/24.
Therefore, B alone needs 24 days.
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Total work is proportional to workers × hours × days.
So days = 8 × 6 × 15 ÷ (12 × 5) = 12.
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To pass a pole, the train covers its own length.
Speed = 150 ÷ 10 = 15 m/s.
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Subtract 7 from both sides of the equation.
This gives x = 19 - 7 = 12.
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An exponent of 1/2 represents a square root.
Thus, 16^(1/2) = √16 = 4.
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Worker-days remain constant for the same job.
Thus, 15 × 20 ÷ 12 = 25 workers.
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Twenty-four workers complete 1/4 in 10 days, so the remaining 3/4 needs 30 equivalent days at the same workforce.
Only 20 days remain, requiring 36 workers, so 12 extra are needed.
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The train covers its length plus the platform length: 300 meters.
Speed = 300 ÷ 20 = 15 m/s.
