Practice MDCAT Chemistry questions with answers and explanations.
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q = mcΔT = 2×4200×5.
The required heat is 42000 J.
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Oxidation numbers sum to the overall charge of the species.
Applying standard rules gives the stated value.
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q = mcΔT = 0.5×400×30.
The required heat is 6000 J.
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Oxidation numbers sum to the overall charge of the species.
Applying standard rules gives the stated value.
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q = mcΔT = 1.2×900×10.
The required heat is 10800 J.
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Oxidation numbers sum to the overall charge of the species.
Applying standard rules gives the stated value.
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q = mcΔT = 0.25×380×40.
The required heat is 3800 J.
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For standard reduction potentials, E°cell = E°cathode − E°anode.
The positive result indicates a spontaneous standard cell reaction.
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q = mcΔT = 3×500×8.
The required heat is 12000 J.
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For standard reduction potentials, E°cell = E°cathode − E°anode.
The positive result indicates a spontaneous standard cell reaction.
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Hess’s law states that enthalpy changes add for sequential steps.
The overall value is the algebraic sum of the two changes.
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For standard reduction potentials, E°cell = E°cathode − E°anode.
The positive result indicates a spontaneous standard cell reaction.
