How many kelvins correspond to 27°C approximately?
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Kelvin temperature is Celsius temperature plus about 273.
27+273 = 300 K.
Practice MDCAT Physics questions with answers and explanations.
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Kelvin temperature is Celsius temperature plus about 273.
27+273 = 300 K.
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Amplitude measures the largest excursion from equilibrium.
It affects energy but not the ideal SHM period.
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Celsius temperature is kelvin temperature minus about 273.
310-273 = 37°C.
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Use Q=mcΔT.
Q=2×4200×5 = 42,000 J.
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Use ΔT=Q/(mc).
6000/(0.5×400)=30°C.
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Use Q=mL.
Q=3×334,000 = 1,002,000 J.
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Use α=ΔL/(LΔT).
α=0.002/(2×50)=2×10^-5 °C^-1.
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Boyle's law gives P1V1=P2V2.
P2=100×4/2 = 200 kPa.
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Charles's law gives V/T constant.
V2=3×400/300 = 4 L.
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The ideal-gas equation gives PV=nRT.
PV=2×8.31×300 = 4986 J.
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Using ΔU=Q-W for work done by the gas.
ΔU=500-200 = 300 J.
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Take Q=-400 J and work done by the gas W=-100 J.
ΔU=Q-W=-400-(-100)=-300 J.