A 2 kg object moving at 5 m/s rebounds at 3 m/s in the opposite direction. What is the magnitude of its momentum change?
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Take initial velocity as +5 and final as -3.
|Δp|=|2(-3-5)|=16 kg·m/s.
Practice MDCAT Physics questions with answers and explanations.
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Take initial velocity as +5 and final as -3.
|Δp|=|2(-3-5)|=16 kg·m/s.
Choose an option to check your answer.
Force equals pressure times area.
F=5000×0.02 = 100 N.
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A body in rotational equilibrium has no angular acceleration.
Clockwise and counterclockwise torques balance.
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Torque is force times perpendicular distance.
τ=10×0.5 = 5 N·m.
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Work is W=Fd when force and displacement are parallel.
W=20×5 = 100 J.
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Torque is rF sinθ.
τ=2×20×sin30° = 20 N·m.
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Use W=Fd cosθ.
W=10×4×cos60° = 20 J.
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Angular velocity is angular displacement divided by time.
ω=10/2 = 5 rad/s.
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Kinetic energy is ½mv².
K=½×4×9 = 18 J.
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Angular acceleration is change in angular velocity over time.
α=(16-4)/3 = 4 rad/s².
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K=½mv².
K=½×2×100 = 100 J.
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Linear speed is v=rω.
V=0.5×8 = 4 m/s.