An object moves from x=2 m to x=14 m in 4 s. What is its average velocity?
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Displacement is 14-2 = 12 m.
Average velocity is 12/4 = 3 m/s.
Practice NAT Physics questions with answers and explanations.
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Displacement is 14-2 = 12 m.
Average velocity is 12/4 = 3 m/s.
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Integrating velocity over time gives displacement.
Areas below the time axis count as negative displacement.
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Average speed uses total distance.
400/80 = 5 m/s.
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Use the Pythagorean theorem for perpendicular components.
Magnitude = √(3²+4²)=5.
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The x-component is A cosθ.
10 cos60° = 10×0.5 = 5.
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The y-component is A sinθ.
10 sin30° = 10×0.5 = 5.
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Vectors in the same direction add directly.
The resultant is 12+7 = 19 N.
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Opposite collinear vectors subtract in magnitude.
The resultant magnitude is |12-7| = 5 N.
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Percentage error is |48-50|/50×100.
The result is 2/50×100 = 4%.
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Move the decimal four places to the right to obtain 7.2.
Therefore the exponent is -4.
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One metre equals 100 centimetres.
Therefore 250 cm ÷ 100 = 2.5 m.
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The metre is the SI base unit of length.
Other metric length units are derived from it using prefixes.