What is the difference between compound and simple interest on Rs. 10,000 at 10% for 2 years?
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For two years, the difference is P(r/100)².
So 10,000 × 0.1² = Rs. 100.
Practice NET Mathematics questions with answers and explanations.
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For two years, the difference is P(r/100)².
So 10,000 × 0.1² = Rs. 100.
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Doubling means interest equal to the principal is earned in 8 years.
Tripling requires interest equal to twice the principal, so it takes 16 years.
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One-year compound amount is principal plus 12% interest.
Thus, 20,000 × 1.12 = Rs. 22,400.
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Initially, milk is 42 liters and water is 18 liters.
For a 7:5 ratio with 42 liters milk, water must be 30 liters, so add 12.
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For inverse variation, xy is constant.
Since 12 × 4 = 48, x = 48/6 = 8.
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Two centimeters represent 100,000 centimeters in reality.
Since 100,000 cm = 1 km, the answer is 1 kilometer.
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The difference of ratio parts is 5, corresponding to 35.
One part is 7, so the larger number is 9 × 7 = 63.
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Five parts equal Rs. 50,000, so one part is Rs. 10,000.
Expenditure is four parts, leaving one part as saving.
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Six consecutive integers centered at 17.5 are 15 through 20.
Therefore, the smallest is 15.
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The average of 1 through n is (n + 1)/2.
Setting (n + 1)/2 = 20 gives n = 39.
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The difference between C and A is 2 ratio parts, equal to Rs. 600.
One part is Rs. 300, so 12 parts total Rs. 3,600.
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Total equals average multiplied by the number of values.
Thus, 24 × 5 = 120.