MCQ Collection
Australia & New Zealand MCQs
Practice Australia & New Zealand questions with answers and explanations.
Choose an option to check your answer.
A.
50
B.
6.25
C.
12.5
D.
25
Show Answer
Correct Answer: C. 12.5
Explanation:
After three half-lives, (1/2)^3=12.5%.
Choose an option to check your answer.
A.
A competitive antagonist usually shifts the agonist concentration–response curve to the right without reducing the maximal response.
B.
It removes the need for agonist binding.
C.
It irreversibly increases efficacy.
D.
It always raises the maximal response.
Show Answer
Correct Answer: A. A competitive antagonist usually shifts the agonist concentration–response curve to the right without reducing the maximal response.
Explanation:
A competitive antagonist usually shifts the agonist concentration–response curve to the right without reducing the maximal response.
Choose an option to check your answer.
A.
It always decreases surface area.
B.
It eliminates first-pass metabolism.
C.
Reducing particle size can increase dissolution rate by increasing surface area.
D.
It guarantees chemical stability.
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Correct Answer: C. Reducing particle size can increase dissolution rate by increasing surface area.
Explanation:
Reducing particle size can increase dissolution rate by increasing surface area.
Choose an option to check your answer.
A.
10.0
B.
4.2
C.
1.0
D.
0.1
Show Answer
Correct Answer: A. 10.0
Explanation:
For a weak acid, [A−]/[HA]=10^(pH−pKa).
Choose an option to check your answer.
A.
A case report proves population causality.
B.
A randomised controlled design reduces allocation bias and supports causal inference when well conducted.
C.
Blinding always increases sample size.
D.
Randomisation guarantees zero measurement error.
Show Answer
Correct Answer: B. A randomised controlled design reduces allocation bias and supports causal inference when well conducted.
Explanation:
A randomised controlled design reduces allocation bias and supports causal inference when well conducted.
Choose an option to check your answer.
A.
It is independent of prevalence.
B.
It must be 100% when specificity is above 50%.
C.
Positive predictive value depends on disease prevalence as well as test performance.
D.
It is always equal to sensitivity.
Show Answer
Correct Answer: C. Positive predictive value depends on disease prevalence as well as test performance.
Explanation:
Positive predictive value depends on disease prevalence as well as test performance.
Choose an option to check your answer.
A.
It guarantees immediate peak concentration.
B.
A depot formulation can prolong drug release and reduce dosing frequency.
C.
It is identical to an intravenous bolus.
D.
It prevents every adverse effect.
Show Answer
Correct Answer: B. A depot formulation can prolong drug release and reduce dosing frequency.
Explanation:
A depot formulation can prolong drug release and reduce dosing frequency.
Choose an option to check your answer.
A.
16.36
B.
18.36
C.
24882
D.
0.061
Show Answer
Correct Answer: A. 16.36
Explanation:
Concentration=amount/volume.
Choose an option to check your answer.
A.
15.0
B.
480.0
C.
0.133
D.
7.5
Show Answer
Correct Answer: D. 7.5
Explanation:
Apply AUC=F×Dose/CL.
Choose an option to check your answer.
A.
6.25
B.
12.5
C.
25
D.
50
Show Answer
Correct Answer: B. 12.5
Explanation:
After three half-lives, (1/2)^3=12.5%.
Choose an option to check your answer.
A.
It irreversibly increases efficacy.
B.
A competitive antagonist usually shifts the agonist concentration–response curve to the right without reducing the maximal response.
C.
It removes the need for agonist binding.
D.
It always raises the maximal response.
Show Answer
Correct Answer: B. A competitive antagonist usually shifts the agonist concentration–response curve to the right without reducing the maximal response.
Explanation:
A competitive antagonist usually shifts the agonist concentration–response curve to the right without reducing the maximal response.
Choose an option to check your answer.
A.
Reducing particle size can increase dissolution rate by increasing surface area.
B.
It guarantees chemical stability.
C.
It always decreases surface area.
D.
It eliminates first-pass metabolism.
Show Answer
Correct Answer: A. Reducing particle size can increase dissolution rate by increasing surface area.
Explanation:
Reducing particle size can increase dissolution rate by increasing surface area.