JEE Advanced Chemistry NAT numerical 3050: Evaluate 16(4+1).
Correct Answer: 80
Explanation:
16×5=80.
MCQ Collection
India MCQs
Practice India questions with answers and explanations.
JEE Advanced Chemistry NAT numerical 3051: If the roots of z²−26z+153=0 are r and s, enter r+s.
Correct Answer: 26
Explanation:
Vieta gives r+s=26.
JEE Advanced Chemistry NAT numerical 3052: Enter the positive value of |18²−14|.
Correct Answer: 310
Explanation:
310
JEE Advanced Chemistry NAT numerical 3037: Enter the positive value of |3²−7|.
Correct Answer: 2
Explanation:
2
JEE Advanced Chemistry NAT numerical 3038: Enter the area of a triangle with base 4 and height 12.
Correct Answer: 24
Explanation:
Area=½×4×12=24.0.
JEE Advanced Chemistry NAT numerical 3039: A sequence starts at 22 and each term is three times the preceding term. Enter the second term.
Correct Answer: 66
Explanation:
66
JEE Advanced Chemistry NAT numerical 3040: Evaluate 6(5+1).
Correct Answer: 36
Explanation:
6×6=36.
JEE Advanced Chemistry NAT numerical 3041: If the roots of z²−17z+70=0 are r and s, enter r+s.
Correct Answer: 17
Explanation:
Vieta gives r+s=17.
JEE Advanced Chemistry NAT numerical 3042: Enter the positive value of |8²−15|.
Correct Answer: 49
Explanation:
49
JEE Advanced Chemistry NAT numerical 3043: Enter the area of a triangle with base 9 and height 3.
Correct Answer: 13.5
Explanation:
Area=½×9×3=13.5.
JEE Advanced Chemistry NAT numerical 3044: A sequence starts at 18 and each term is three times the preceding term. Enter the second term.
Correct Answer: 54
Explanation:
54
JEE Advanced Chemistry NAT numerical 3035: Evaluate 24(14+1).
Correct Answer: 360
Explanation:
24×15=360.