JEE Advanced Chemistry NAT numerical 3032: Enter the positive value of |21²−16|.
Correct Answer: 425
Explanation:
425
MCQ Collection
India MCQs
Practice India questions with answers and explanations.
JEE Advanced Chemistry NAT numerical 3033: Enter the area of a triangle with base 22 and height 4.
Correct Answer: 44
Explanation:
Area=½×22×4=44.0.
JEE Advanced Chemistry NAT numerical 3034: A sequence starts at 32 and each term is three times the preceding term. Enter the second term.
Correct Answer: 96
Explanation:
96
JEE Advanced Physics NAT numerical 3008: Enter the area of a triangle with base 20 and height 15.
Correct Answer: 150
Explanation:
Area=½×20×15=150.0.
JEE Advanced Physics NAT numerical 3009: A sequence starts at 24 and each term is three times the preceding term. Enter the second term.
Correct Answer: 72
Explanation:
72
JEE Advanced Physics NAT numerical 3010: Evaluate 22(8+1).
Correct Answer: 198
Explanation:
22×9=198.
JEE Advanced Physics NAT numerical 3011: If the roots of z²−36z+299=0 are r and s, enter r+s.
Correct Answer: 36
Explanation:
Vieta gives r+s=36.
JEE Advanced Physics NAT numerical 3012: Enter the positive value of |24²−18|.
Correct Answer: 558
Explanation:
558
JEE Advanced Physics NAT numerical 3013: Enter the area of a triangle with base 2 and height 6.
Correct Answer: 6
Explanation:
Area=½×2×6=6.0.
JEE Advanced Physics NAT numerical 3014: A sequence starts at 14 and each term is three times the preceding term. Enter the second term.
Correct Answer: 42
Explanation:
42
JEE Advanced Physics NAT numerical 3015: Evaluate 4(16+1).
Correct Answer: 68
Explanation:
4×17=68.
JEE Advanced Physics NAT numerical 3016: If the roots of z²−9z+20=0 are r and s, enter r+s.
Correct Answer: 9
Explanation:
Vieta gives r+s=9.