EJU Mathematics Course 1 practice 91: How many ways can 3 students be selected from 6 students?
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Use combinations: C(6,3) = 20.
Practice Japan questions with answers and explanations.
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Use combinations: C(6,3) = 20.
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Probability = favourable outcomes ÷ total outcomes.
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Mean = (9 + 12 + 3 + 21)/4 = 11.25.
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f(7)=6×7+7=49.
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Use combinations: C(12,4) = 495.
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Probability = favourable outcomes ÷ total outcomes.
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Mean = (2 + 10 + 2 + 12)/4 = 6.50.
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f(7)=4×7+8=36.
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Area = 17 × 7 = 119 cm².
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By Vieta’s formula, the sum of the roots is the coefficient of x with sign changed.
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Use combinations: C(11,2) = 55.
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Probability = favourable outcomes ÷ total outcomes.