EJU Mathematics Course 1 practice 67: How many ways can 3 students be selected from 10 students?
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Use combinations: C(10,3) = 120.
Practice Japan questions with answers and explanations.
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Use combinations: C(10,3) = 120.
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Probability = favourable outcomes ÷ total outcomes.
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Use combinations: C(8,2) = 28.
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Probability = favourable outcomes ÷ total outcomes.
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Mean = (8 + 21 + 9 + 29)/4 = 16.75.
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f(7)=2×7+3=17.
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10% of 46 = 4.6.
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Area = 3 × 3 = 9 cm².
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By Vieta’s formula, the sum of the roots is the coefficient of x with sign changed.
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Use combinations: C(9,4) = 126.
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Probability = favourable outcomes ÷ total outcomes.
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Mean = (15 + 4 + 10 + 19)/4 = 12.