Practice Pakistan questions with answers and explanations.
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Average the x-coordinates and the y-coordinates separately.
The midpoint is ((2 + 8)/2, (3 + 7)/2) = (5, 5).
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Curved surface area is 2πrh.
Thus, 2π × 4 × 7 = 56π cm².
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Cone volume is one-third πr²h.
Thus, 1/3 × π × 9 × 12 = 36π cm³.
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Sphere volume is 4/3 πr³.
Thus, 4/3 × π × 27 = 36π cm³.
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The edge length is the cube root of the volume.
Since 6³ = 216, the edge is 6 cm.
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Distance is √[(3 - 0)² + (4 - 0)²].
This equals √25 = 5.
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Area is one-half × sum of parallel sides × height.
Thus, 1/2 × 22 × 5 = 55 cm².
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Circumference is 2πr.
Thus, 2 × 22/7 × 7 = 44 cm.
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Circle area is πr².
Thus, 22/7 × 49 = 154 cm².
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A 90° arc is one quarter of the circumference.
The circumference is 88 cm, so the arc is 22 cm.
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Sector area is angle/360 × πr².
Thus, 60/360 × 36π = 6π cm².
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Cube volume is side cubed.
Thus, 4³ = 64 cm³.
