Pakistan MCQs

A cube has six square faces, each of area 25 cm².
Thus, total area is 6 × 25 = 150 cm².

Cuboid volume is length × width × height.
Thus, 8 × 5 × 3 = 120 cm³.

Cylinder volume is πr²h.
Thus, π × 9 × 10 = 90π cm³.

Lone pairs influence shape and reactivity.
They repel bonding pairs strongly in VSEPR theory.

Each carbon has two electron domains.
Sp hybridization gives linear geometry and leaves two p orbitals for pi bonds.

A single bond has order one, double bond two, and triple bond three.
Higher bond order generally means shorter, stronger bonds.

Rectangle perimeter is 2(length + width).
Thus, 2(8 + 5) = 26 cm.

Triple bonds have higher bond order than single or double bonds.
They are usually shorter and stronger.

Rectangle area is length multiplied by width.
Thus, 12 × 7 = 84 m².

No single resonance structure fully represents the electron distribution.
The real structure is a resonance hybrid.

Square area is side squared.
Thus, 9² = 81 cm².

Formal charge helps compare possible Lewis structures.
Preferred structures often minimize charge separation.