What is hybridization of carbon in CH4?
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Four equivalent bonding directions correspond to sp3 hybridization.
The ideal geometry is tetrahedral.
Practice NAT Chemistry questions with answers and explanations.
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Four equivalent bonding directions correspond to sp3 hybridization.
The ideal geometry is tetrahedral.
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Each carbon has three sigma-bonding regions.
The remaining p orbitals form the pi bond.
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Lone pairs influence shape and reactivity.
They repel bonding pairs strongly in VSEPR theory.
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Each carbon has two electron domains.
Sp hybridization gives linear geometry and leaves two p orbitals for pi bonds.
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A single bond has order one, double bond two, and triple bond three.
Higher bond order generally means shorter, stronger bonds.
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Triple bonds have higher bond order than single or double bonds.
They are usually shorter and stronger.
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No single resonance structure fully represents the electron distribution.
The real structure is a resonance hybrid.
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Formal charge helps compare possible Lewis structures.
Preferred structures often minimize charge separation.
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Electron groups arrange to minimize repulsion.
Lone pairs and bonding regions determine molecular geometry.
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Two electron groups arrange 180 degrees apart.
This minimizes repulsion.
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Three electron groups arrange about 120 degrees apart.
They lie in one plane.
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Four electron groups point toward tetrahedral corners.
The ideal bond angle is about 109.5 degrees.