Senior-secondary mathematics task 60: In a sample of 25 items, 10 meet a condition. Enter the percentage, rounded to two decimals.
Percentage=(10/25)×100=40.00.
Practice china-gaokao-mathematics questions with answers and explanations.
Percentage=(10/25)×100=40.00.
Subtract 9 from both sides and divide by 8: x = (65-9)/8 = 7.
By Vieta’s formula, the sum of the roots equals the coefficient 14.
aₙ=a₁+(n−1)d=8+(11−1)×1=18.
Percentage=(9/24)×100=37.50.
Subtract 8 from both sides and divide by 7: x = (50-8)/7 = 6.
By Vieta’s formula, the sum of the roots equals the coefficient 11.
aₙ=a₁+(n−1)d=7+(10−1)×6=61.
Choose an option to check your answer.
The sum is n(n+1)/2=45, so the mean is 45/9.
Choose an option to check your answer.
There are 2 favourable outcomes out of 10 equally likely outcomes, so P(red)=2/10.
The coordinate differences are 3 and 4, so the distance is √(3²+4²)=5.
f′(x)=3x²+14x. Substituting x=2 gives 40.