Senior-secondary mathematics task 56: Evaluate ∫₀^3 (2x+1) dx.
An antiderivative is 2/2 x²+1x. At x=3, the value is 12.0.
Practice china-gaokao-mathematics questions with answers and explanations.
An antiderivative is 2/2 x²+1x. At x=3, the value is 12.0.
aₙ=a₁+(n−1)d=6+(9−1)×5=46.
Choose an option to check your answer.
The sum is n(n+1)/2=36, so the mean is 36/8.
Choose an option to check your answer.
There are 6 favourable outcomes out of 13 equally likely outcomes, so P(red)=6/13.
The coordinate differences are 3 and 4, so the distance is √(3²+4²)=5.
f′(x)=15x²+12x. Substituting x=1 gives 27.
An antiderivative is 1/2 x²+5x. At x=2, the value is 12.0.
The dot product is 1×3+6×5=33.
Rewrite the value using base 2: 4 = 2^2. Matching exponents gives x = 2.
Choose an option to check your answer.
Use the circle-area formula A = πr². Substituting r = 6 gives A = π × 6² = 36π.
Percentage=(8/23)×100=34.78.
Subtract 7 from both sides and divide by 6: x = (37-7)/6 = 5.