Practice IBA Undergraduate Aptitude questions with answers and explanations.
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The amount is 8,000 × 1.05² = Rs. 8,820.
Subtracting the principal gives compound interest of Rs. 820.
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For two years, the difference is P(r/100)².
So 10,000 × 0.1² = Rs. 100.
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Let the numbers be 5k and 8k; then (5k + 9)/(8k + 9) = 2/3.
Solving gives k = 9, so the smaller number is 45.
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The original total age is 4 × 25 = 100 years.
The new total is 5 × 27 = 135, so the new age is 35.
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Profit equals selling price minus cost price.
Thus, 920 - 800 = Rs. 120.
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The weighted sum is 70 × 2 + 90 × 3 = 410.
Dividing by the total weight 5 gives 82.
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A 10% loss on Rs. 1,200 is Rs. 120.
Subtracting gives a selling price of Rs. 1,080.
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The total score is 20 × 60 + 30 × 70 = 3,300.
Dividing by 50 students gives 66.
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The total ratio parts are 7, so one part is 35/7 = 5 liters.
Water is two parts, or 10 liters.
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Thirty percent of 20 liters is 0.30 × 20.
This equals 6 liters.
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The solution contains 4 liters of salt, which remains unchanged.
For salt to be 25%, total volume must be 16 liters, so 6 liters are added.
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For direct variation, x/y is constant.
The constant is 18/6 = 3, so x = 3 × 10 = 30.
