Practice IBA Undergraduate Aptitude questions with answers and explanations.
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Move variable terms to one side and constants to the other.
Then 3x = 15, so x = 5.
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Downstream speed equals still-water speed plus stream speed.
Thus, 12 + 3 = 15 km/h.
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Upstream speed equals still-water speed minus stream speed.
Thus, 10 - 2 = 8 km/h.
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Downstream speed is 15 km/h and upstream speed is 10 km/h.
Still-water speed is their average: 12.5 km/h.
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In the same time, the faster runner covers 1,000 m while the slower covers 900 m.
Their speed ratio is therefore 1,000:900 = 10:9.
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Time is inversely proportional to speed.
The decrease is 1 - 50/60 = 1/6 = 16 2/3%.
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Let total distance be 3d; time is d/30 + 2d/60 = d/15.
Average speed is 3d ÷ (d/15) = 45 km/h.
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Travel time is 210 ÷ 70 = 3 hours.
Three hours after 8:00 a.m. is 11:00 a.m.
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Their closing speed is 20 + 25 = 45 km/h.
Time = 90 ÷ 45 = 2 hours.
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For equal distances, average speed is the harmonic mean 2ab/(a + b).
Thus, 2 × 40 × 60 ÷ 100 = 48 km/h.
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The path forms a right triangle with legs 5 and 12.
By Pythagoras, distance is √(25 + 144) = 13 km.
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For equal time intervals, average speed is the arithmetic mean.
Thus, (40 + 60)/2 = 50 km/h.
