Practice NET Engineering questions with answers and explanations.
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The amount is 8,000 × 1.05² = Rs. 8,820.
Subtracting the principal gives compound interest of Rs. 820.
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For two years, the difference is P(r/100)².
So 10,000 × 0.1² = Rs. 100.
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Doubling means interest equal to the principal is earned in 8 years.
Tripling requires interest equal to twice the principal, so it takes 16 years.
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One-year compound amount is principal plus 12% interest.
Thus, 20,000 × 1.12 = Rs. 22,400.
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Profit is shared in the ratio of investments, 3:5.
B receives 5/8 of Rs. 16,000 = Rs. 10,000.
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Let the numbers be 5k and 8k; then (5k + 9)/(8k + 9) = 2/3.
Solving gives k = 9, so the smaller number is 45.
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Capital-time products are 40,000 × 12 and 60,000 × 8.
Both equal 480,000, so the ratio is 1:1.
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Profit equals selling price minus cost price.
Thus, 920 - 800 = Rs. 120.
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A's capital-time is 2 × 6 + 4 × 6 = 36 units.
B's is 3 × 12 = 36 units, so profits are equal.
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A 10% loss on Rs. 1,200 is Rs. 120.
Subtracting gives a selling price of Rs. 1,080.
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A 20% profit gives a selling price of Rs. 960.
Since this is 80% of marked price, marked price = 960/0.8 = Rs. 1,200.
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The selling price is 125% of the cost price.
Thus, cost price = 1,500 ÷ 1.25 = Rs. 1,200.
