NET Engineering MCQs

He charges for 1,000 grams but supplies only 900 grams.
Gain percentage is 100/900 × 100 = 11 1/9%.

The discount is 15% of Rs. 2,000, which is Rs. 300.
The sale price is Rs. 2,000 - Rs. 300 = Rs. 1,700.

After a 10% discount, 90% remains; after another 20%, 80% of that remains.
The final price is 72%, so the total discount is 28%.

Let cost be 100; marked price is 125 and sale price is 90% of 125 = 112.5.
The profit is 12.5 on a cost of 100.

Simple interest is PRT/100.
So 5,000 × 8 × 3 ÷ 100 = Rs. 1,200.

For inverse variation, xy is constant.
Since 12 × 4 = 48, x = 48/6 = 8.

Two centimeters represent 100,000 centimeters in reality.
Since 100,000 cm = 1 km, the answer is 1 kilometer.

The difference of ratio parts is 5, corresponding to 35.
One part is 7, so the larger number is 9 × 7 = 63.

Five parts equal Rs. 50,000, so one part is Rs. 10,000.
Expenditure is four parts, leaving one part as saving.

Six consecutive integers centered at 17.5 are 15 through 20.
Therefore, the smallest is 15.

The average of 1 through n is (n + 1)/2.
Setting (n + 1)/2 = 20 gives n = 39.

The difference between C and A is 2 ratio parts, equal to Rs. 600.
One part is Rs. 300, so 12 parts total Rs. 3,600.