MCQ Collection
opra MCQs
Practice opra questions with answers and explanations.
Choose an option to check your answer.
A.
0.063
B.
2275.2
C.
15.8
D.
26.33
Show Answer
Correct Answer: C. 15.8
Explanation:
Apply AUC=F×Dose/CL.
Choose an option to check your answer.
A.
50
B.
6.25
C.
12.5
D.
25
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Correct Answer: C. 12.5
Explanation:
After three half-lives, (1/2)^3=12.5%.
Choose an option to check your answer.
A.
It irreversibly increases efficacy.
B.
It removes the need for agonist binding.
C.
A competitive antagonist usually shifts the agonist concentration–response curve to the right without reducing the maximal response.
D.
It always raises the maximal response.
Show Answer
Correct Answer: C. A competitive antagonist usually shifts the agonist concentration–response curve to the right without reducing the maximal response.
Explanation:
A competitive antagonist usually shifts the agonist concentration–response curve to the right without reducing the maximal response.
Choose an option to check your answer.
A.
It eliminates first-pass metabolism.
B.
It always decreases surface area.
C.
Reducing particle size can increase dissolution rate by increasing surface area.
D.
It guarantees chemical stability.
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Correct Answer: C. Reducing particle size can increase dissolution rate by increasing surface area.
Explanation:
Reducing particle size can increase dissolution rate by increasing surface area.
Choose an option to check your answer.
A.
1.0
B.
10.0
C.
6.0
D.
0.1
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Correct Answer: B. 10.0
Explanation:
For a weak acid, [A−]/[HA]=10^(pH−pKa).
Choose an option to check your answer.
A.
Bactericidal activity kills susceptible bacteria, whereas bacteriostatic activity inhibits growth.
B.
Both terms mean viral inactivation.
C.
Bacteriostatic agents always destroy spores.
D.
Bactericidal agents cannot have resistance.
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Correct Answer: A. Bactericidal activity kills susceptible bacteria, whereas bacteriostatic activity inhibits growth.
Explanation:
Bactericidal activity kills susceptible bacteria, whereas bacteriostatic activity inhibits growth.
Choose an option to check your answer.
A.
Phase I reactions occur only outside the body.
B.
Phase I is limited to renal filtration.
C.
Phase I always produces an inactive metabolite.
D.
Phase I reactions commonly introduce or expose functional groups through oxidation, reduction or hydrolysis.
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Correct Answer: D. Phase I reactions commonly introduce or expose functional groups through oxidation, reduction or hydrolysis.
Explanation:
Phase I reactions commonly introduce or expose functional groups through oxidation, reduction or hydrolysis.
Choose an option to check your answer.
A.
66.1
B.
151.3
C.
41.4
D.
99.6
Show Answer
Correct Answer: A. 66.1
Explanation:
Use fraction remaining=e^(−kt).
Choose an option to check your answer.
A.
Blinding always increases sample size.
B.
Randomisation guarantees zero measurement error.
C.
A randomised controlled design reduces allocation bias and supports causal inference when well conducted.
D.
A case report proves population causality.
Show Answer
Correct Answer: C. A randomised controlled design reduces allocation bias and supports causal inference when well conducted.
Explanation:
A randomised controlled design reduces allocation bias and supports causal inference when well conducted.
Choose an option to check your answer.
A.
6.25
B.
25
C.
50
D.
12.5
Show Answer
Correct Answer: D. 12.5
Explanation:
After three half-lives, (1/2)^3=12.5%.
Choose an option to check your answer.
A.
A competitive antagonist usually shifts the agonist concentration–response curve to the right without reducing the maximal response.
B.
It always raises the maximal response.
C.
It removes the need for agonist binding.
D.
It irreversibly increases efficacy.
Show Answer
Correct Answer: A. A competitive antagonist usually shifts the agonist concentration–response curve to the right without reducing the maximal response.
Explanation:
A competitive antagonist usually shifts the agonist concentration–response curve to the right without reducing the maximal response.
Choose an option to check your answer.
A.
It guarantees chemical stability.
B.
Reducing particle size can increase dissolution rate by increasing surface area.
C.
It eliminates first-pass metabolism.
D.
It always decreases surface area.
Show Answer
Correct Answer: B. Reducing particle size can increase dissolution rate by increasing surface area.
Explanation:
Reducing particle size can increase dissolution rate by increasing surface area.
