Question
A gas occupies 3 L at 120 kPa. At constant temperature its volume becomes 6 L. What is the new pressure?
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Correct Answer: C. 60 kPa
Explanation:
Boyle’s law gives P₁V₁ = P₂V₂.
P₂ = 120×3÷6 = 60 kPa.
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