Question
How many moles are in 24.6 L of an ideal gas at 300 K and 100 kPa using R=8.31 L·kPa/mol·K?
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Correct Answer: A. 0.987 mol
Explanation:
Use n=PV/RT.
N=100×24.6/(8.31×300)≈0.987 mol.
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