Postgraduate Mathematics III task 118: If 5^x=3125, enter x.
Rewrite the value using base 5: 3125 = 5^5. Matching exponents gives x = 5.
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Rewrite the value using base 5: 3125 = 5^5. Matching exponents gives x = 5.
The dot product is 4×4+3×6=34.
An antiderivative is 4/2 x²+2x. At x=5, the value is 60.0.
f′(x)=6x²+6x. Substituting x=4 gives 120.
The coordinate differences are 3 and 4, so the distance is √(3²+4²)=5.
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There are 3 favourable outcomes out of 11 equally likely outcomes, so P(red)=3/11.
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The sum is n(n+1)/2=15, so the mean is 15/5.
aₙ=a₁+(n−1)d=10+(16−1)×6=100.
By Vieta’s formula, the sum of the roots equals the coefficient 19.
Subtract 11 from both sides and divide by 3: x = (29-11)/3 = 6.
Percentage=(5/30)×100=16.67.
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Use the circle-area formula A = πr². Substituting r = 8 gives A = π × 8² = 64π.