Postgraduate Mathematics III task 94: If 3^x=27, enter x.
Rewrite the value using base 3: 27 = 3^3. Matching exponents gives x = 3.
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Rewrite the value using base 3: 27 = 3^3. Matching exponents gives x = 3.
The dot product is 2×2+6×4=28.
An antiderivative is 2/2 x²+5x. At x=3, the value is 24.0.
f′(x)=15x²+16x. Substituting x=2 gives 92.
The coordinate differences are 3 and 4, so the distance is √(3²+4²)=5.
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There are 6 favourable outcomes out of 12 equally likely outcomes, so P(red)=6/12.
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The sum is n(n+1)/2=55, so the mean is 55/10.
aₙ=a₁+(n−1)d=8+(14−1)×4=60.
By Vieta’s formula, the sum of the roots equals the coefficient 13.
Subtract 9 from both sides and divide by 8: x = (41-9)/8 = 4.
Percentage=(13/28)×100=46.43.
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Use the circle-area formula A = πr². Substituting r = 6 gives A = π × 6² = 36π.