Postgraduate Mathematics III task 34: If 2^x=4, enter x.
Rewrite the value using base 2: 4 = 2^2. Matching exponents gives x = 2.
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Rewrite the value using base 2: 4 = 2^2. Matching exponents gives x = 2.
The dot product is 1×3+6×5=33.
An antiderivative is 1/2 x²+5x. At x=2, the value is 12.0.
f′(x)=15x²+6x. Substituting x=1 gives 21.
The coordinate differences are 3 and 4, so the distance is √(3²+4²)=5.
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There are 6 favourable outcomes out of 13 equally likely outcomes, so P(red)=6/13.
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The sum is n(n+1)/2=15, so the mean is 15/5.
aₙ=a₁+(n−1)d=3+(9−1)×5=43.
By Vieta’s formula, the sum of the roots equals the coefficient 7.
Subtract 4 from both sides and divide by 3: x = (34-4)/3 = 10.
Percentage=(8/23)×100=34.78.
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Use the circle-area formula A = πr². Substituting r = 9 gives A = π × 9² = 81π.