Postgraduate Mathematics III task 22: If 5^x=3125, enter x.
Rewrite the value using base 5: 3125 = 5^5. Matching exponents gives x = 5.
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Rewrite the value using base 5: 3125 = 5^5. Matching exponents gives x = 5.
The dot product is 4×2+5×4=28.
An antiderivative is 4/2 x²+4x. At x=5, the value is 70.0.
f′(x)=12x²+4x. Substituting x=4 gives 208.
The coordinate differences are 3 and 4, so the distance is √(3²+4²)=5.
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There are 5 favourable outcomes out of 11 equally likely outcomes, so P(red)=5/11.
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The sum is n(n+1)/2=10, so the mean is 10/4.
aₙ=a₁+(n−1)d=2+(8−1)×4=30.
By Vieta’s formula, the sum of the roots equals the coefficient 12.
Subtract 3 from both sides and divide by 2: x = (21-3)/2 = 9.
Percentage=(7/22)×100=31.82.
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Use the circle-area formula A = πr². Substituting r = 8 gives A = π × 8² = 64π.