Postgraduate Mathematics II task 118: If 5^x=3125, enter x.
Rewrite the value using base 5: 3125 = 5^5. Matching exponents gives x = 5.
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Rewrite the value using base 5: 3125 = 5^5. Matching exponents gives x = 5.
The dot product is 4×4+4×6=40.
An antiderivative is 4/2 x²+3x. At x=5, the value is 65.0.
f′(x)=9x²+14x. Substituting x=4 gives 200.
The coordinate differences are 3 and 4, so the distance is √(3²+4²)=5.
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There are 4 favourable outcomes out of 12 equally likely outcomes, so P(red)=4/12.
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The sum is n(n+1)/2=45, so the mean is 45/9.
aₙ=a₁+(n−1)d=4+(16−1)×6=94.
By Vieta’s formula, the sum of the roots equals the coefficient 16.
Subtract 5 from both sides and divide by 7: x = (33-5)/7 = 4.
Percentage=(11/36)×100=30.56.
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Use the circle-area formula A = πr². Substituting r = 8 gives A = π × 8² = 64π.