Postgraduate Mathematics II task 106: If 4^x=256, enter x.
Rewrite the value using base 4: 256 = 4^4. Matching exponents gives x = 4.
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Rewrite the value using base 4: 256 = 4^4. Matching exponents gives x = 4.
The dot product is 3×3+3×5=24.
An antiderivative is 3/2 x²+2x. At x=4, the value is 32.0.
f′(x)=6x²+12x. Substituting x=3 gives 90.
The coordinate differences are 3 and 4, so the distance is √(3²+4²)=5.
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There are 3 favourable outcomes out of 10 equally likely outcomes, so P(red)=3/10.
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The sum is n(n+1)/2=36, so the mean is 36/8.
aₙ=a₁+(n−1)d=3+(15−1)×5=73.
By Vieta’s formula, the sum of the roots equals the coefficient 13.
Subtract 4 from both sides and divide by 6: x = (22-4)/6 = 3.
Percentage=(10/35)×100=28.57.
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Use the circle-area formula A = πr². Substituting r = 7 gives A = π × 7² = 49π.