Postgraduate Mathematics II task 70: If 5^x=3125, enter x.
Rewrite the value using base 5: 3125 = 5^5. Matching exponents gives x = 5.
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Rewrite the value using base 5: 3125 = 5^5. Matching exponents gives x = 5.
The dot product is 4×3+5×2=22.
An antiderivative is 4/2 x²+4x. At x=5, the value is 70.0.
f′(x)=12x²+6x. Substituting x=4 gives 216.
The coordinate differences are 3 and 4, so the distance is √(3²+4²)=5.
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There are 5 favourable outcomes out of 9 equally likely outcomes, so P(red)=5/9.
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The sum is n(n+1)/2=15, so the mean is 15/5.
aₙ=a₁+(n−1)d=9+(12−1)×2=31.
By Vieta’s formula, the sum of the roots equals the coefficient 13.
Subtract 10 from both sides and divide by 3: x = (43-10)/3 = 11.
Percentage=(7/32)×100=21.88.
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Use the circle-area formula A = πr². Substituting r = 4 gives A = π × 4² = 16π.