Postgraduate Mathematics II task 58: If 4^x=256, enter x.
Rewrite the value using base 4: 256 = 4^4. Matching exponents gives x = 4.
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Rewrite the value using base 4: 256 = 4^4. Matching exponents gives x = 4.
The dot product is 3×2+4×1=10.
An antiderivative is 3/2 x²+3x. At x=4, the value is 36.0.
f′(x)=9x²+4x. Substituting x=3 gives 93.
The coordinate differences are 3 and 4, so the distance is √(3²+4²)=5.
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There are 4 favourable outcomes out of 7 equally likely outcomes, so P(red)=4/7.
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The sum is n(n+1)/2=10, so the mean is 10/4.
aₙ=a₁+(n−1)d=8+(11−1)×1=18.
By Vieta’s formula, the sum of the roots equals the coefficient 10.
Subtract 9 from both sides and divide by 2: x = (29-9)/2 = 10.
Percentage=(6/31)×100=19.35.
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Use the circle-area formula A = πr². Substituting r = 3 gives A = π × 3² = 9π.