Postgraduate Mathematics I task 34: If 4^x=256, enter x.
Rewrite the value using base 4: 256 = 4^4. Matching exponents gives x = 4.
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Rewrite the value using base 4: 256 = 4^4. Matching exponents gives x = 4.
The dot product is 3×3+4×5=29.
An antiderivative is 3/2 x²+3x. At x=4, the value is 36.0.
f′(x)=9x²+6x. Substituting x=3 gives 99.
The coordinate differences are 3 and 4, so the distance is √(3²+4²)=5.
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There are 4 favourable outcomes out of 11 equally likely outcomes, so P(red)=4/11.
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The sum is n(n+1)/2=15, so the mean is 15/5.
aₙ=a₁+(n−1)d=6+(15−1)×5=76.
By Vieta’s formula, the sum of the roots equals the coefficient 19.
Subtract 7 from both sides and divide by 3: x = (10-7)/3 = 1.
Percentage=(6/41)×100=14.63.
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Use the circle-area formula A = πr². Substituting r = 7 gives A = π × 7² = 49π.