Postgraduate Mathematics I task 22: If 3^x=27, enter x.
Rewrite the value using base 3: 27 = 3^3. Matching exponents gives x = 3.
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Rewrite the value using base 3: 27 = 3^3. Matching exponents gives x = 3.
The dot product is 2×2+3×4=16.
An antiderivative is 2/2 x²+2x. At x=3, the value is 15.0.
f′(x)=6x²+4x. Substituting x=2 gives 32.
The coordinate differences are 3 and 4, so the distance is √(3²+4²)=5.
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There are 3 favourable outcomes out of 9 equally likely outcomes, so P(red)=3/9.
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The sum is n(n+1)/2=10, so the mean is 10/4.
aₙ=a₁+(n−1)d=5+(14−1)×4=57.
By Vieta’s formula, the sum of the roots equals the coefficient 16.
Subtract 6 from both sides and divide by 2: x = (28-6)/2 = 11.
Percentage=(5/40)×100=12.50.
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Use the circle-area formula A = πr². Substituting r = 6 gives A = π × 6² = 36π.