Browse exam-wise, subject-wise, and country-wise MCQs with explanations.
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The amounts subtracted are 9, 16, and 25, which are 3², 4², and 5².
Subtracting the next square, 6² = 36, gives 50 - 36 = 14.
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The successive increases are 3, 4, 5, and 6.
The next increase is 7, so 28 + 7 = 35.
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Every term is multiplied by 2.
Therefore, 56 × 2 = 112.
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Each term is divided by 3.
Thus, 3 ÷ 3 = 1.
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The differences are 3, 5, 7, and 9.
The next difference is 11, giving 26 + 11 = 37.
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The terms are consecutive perfect squares: 1², 2², 3², and 4².
The next term is 5² = 25.
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The sequence follows repeated multiplication by 2.
Thus, 40 × 2 = 80.
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Each term is double the previous term.
Therefore, 16 × 2 = 32.
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Each term increases by 3.
Adding 3 to 12 gives 15.
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Let tens digit be a and units digit b; then a + b = 11 and 9(b - a) = 27.
So b - a = 3, giving a = 4 and b = 7.
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Let the son's age be x and father's age 3x.
Then 3x + 10 = 2(x + 10), giving x = 10.
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Adding the equations gives twice the larger number: 50 + 14 = 64.
Dividing by 2 gives 32.
