Browse exam-wise, subject-wise, and country-wise MCQs with explanations.
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Set x - 3 equal to 5 and -5.
The resulting solutions are x = 8 and x = -2.
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Absolute value gives distance from zero.
Both 7 and -7 are 7 units from zero.
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Dividing an inequality by a negative number reverses the sign.
Thus, x > -4.
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Add 5 to both sides to get 3x > 15.
Dividing by 3 gives x > 5.
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If n ≡ 4 mod 7, then 2n ≡ 8 mod 7.
The remainder of 8 divided by 7 is 1.
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For two positive integers a and b, gcd(a,b) × lcm(a,b) = ab.
This identity links common factors and common multiples.
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The second number is product divided by the first number.
Thus, 216 ÷ 18 = 12.
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The LCM uses prime powers 2³, 3, and 5.
Their product is 8 × 3 × 5 = 120.
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The largest two-digit multiple of 7 is 7 × 14.
This equals 98.
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The digit sum of 568 is 19, which leaves remainder 1 when divided by 9.
Adding 8 makes the digit sum 27, divisible by 9.
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The two largest shares are 35% and 25%.
Their combined share is 60%.
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The increase is 25 on a base of 125.
Thus, 25/125 × 100 = 20%.
