What is each exterior angle of a regular octagon?
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The exterior angles of any polygon sum to 360°.
For a regular octagon, each is 360° ÷ 8 = 45°.
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The exterior angles of any polygon sum to 360°.
For a regular octagon, each is 360° ÷ 8 = 45°.
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The total interior angle sum is 720°.
Dividing by 6 equal angles gives 120°.
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The sum is (n - 2) × 180°.
For n = 5, this is 3 × 180° = 540°.
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Under the common school definition, a trapezium has one pair of parallel sides.
Parallelograms have two pairs.
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A rhombus is defined by four equal sides.
Its angles need not be right angles.
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A rectangle has four right angles and opposite sides equal.
Its diagonals are also equal in length.
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A quadrilateral can be divided into two triangles.
Thus, its angle sum is 2 × 180° = 360°.
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An exterior angle equals the sum of the two remote interior angles.
It is supplementary to the adjacent interior angle.
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For a right triangle, the square of the longest side equals the sum of the other squares.
Here, 5² + 12² = 13².
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By Pythagoras, c² = 6² + 8² = 100.
Thus, c = 10 cm.
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Equal sides in an isosceles triangle face equal angles.
This is the base-angle theorem.
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All three angles are equal and their sum is 180°.
Therefore, each angle is 180° ÷ 3 = 60°.