Simplify: (2a³)².
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Square the coefficient and multiply the exponent by 2.
This gives 2²a⁶ = 4a⁶.
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Square the coefficient and multiply the exponent by 2.
This gives 2²a⁶ = 4a⁶.
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When dividing powers with the same base, subtract the exponents.
Thus, x⁷ ÷ x³ = x⁴.
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When multiplying powers with the same base, add the exponents.
Thus, a³ × a⁵ = a⁸.
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A zero discriminant makes the square-root term in the formula zero.
Both solutions therefore coincide.
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The discriminant is b² - 4ac.
Here it is 4² - 4(1)(1) = 16 - 4 = 12.
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The quadratic factors as (x - 2)(x - 3) = 0.
Therefore, x is 2 or 3.
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The required numbers multiply to 6 and add to 5.
Those numbers are 2 and 3.
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The expression is a difference of squares: x² - 3².
Thus, it factors as (x - 3)(x + 3).
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Substitute x = 2 to obtain 4 + 3y = 13.
Then 3y = 9, so y = 3.
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Adding the equations gives 2x = 14, so x = 7.
Substituting into x + y = 10 gives y = 3.
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Multiply both sides by 4.
Thus, x = 7 × 4 = 28.
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Move variable terms to one side and constants to the other.
Then 3x = 15, so x = 5.